10m^2-19m-15=0

Solution for 10m^2-19m-15=0 equation:

10m^2-19m-15=0

a = 10; b = -19; c = -15;
Δ = b2-4ac
Δ = -192-4·10·(-15)
Δ = 961
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{961}=31$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-19)-31}{2*10}=\frac{-12}{20}
=-3/5
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-19)+31}{2*10}=\frac{50}{20}
=2+1/2
$